0=-16t^2+80t+800

Solution for 0=-16t^2+80t+800 equation:

0=-16t^2+80t+800

We move all terms to the left:

0-(-16t^2+80t+800)=0

We add all the numbers together, and all the variables

-(-16t^2+80t+800)=0

We get rid of parentheses

16t^2-80t-800=0

a = 16; b = -80; c = -800;
Δ = b2-4ac
Δ = -802-4·16·(-800)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-240}{2*16}=\frac{-160}{32}
=-5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+240}{2*16}=\frac{320}{32}
=10
$